Equation of a tangent line of the parabola $y^2=8 x$, which passes through the point $(1,3)$ is
- $y=2 x+1$
- $2 y=x+5$
- $y=-2 x+5$
- $2 y=3 x+3$
Solution
It passes through $(1,3)$ $\Rightarrow 3=m+\frac{2}{m} \Rightarrow m=1,2$ $\therefore$ Tangents are $y=x+2$ and $y=2 x+1$
Asked in: AP EAMCET 2024 (20 May Shift 2)