Enthalpy of neutralisation of $\mathrm{HCl}$ with $\mathrm{NaOH}$ is $x$. The heat evolved when $500…
Enthalpy of neutralisation of $\mathrm{HCl}$ with $\mathrm{NaOH}$ is $x$. The heat evolved when $500 \mathrm{~mL}$ of $2 \mathrm{~N} \mathrm{HCl}$ are mixed with $250 \mathrm{~mL}$ of $4 \mathrm{~N} \mathrm{NaOH}$ will be.
$500 \mathrm{x}$
$100 x$
$x$
$10 \mathrm{x}$
Solution
Enthalpy of neutralisation of $\mathrm{HCl}$ with $\mathrm{NaOH}$ is $\mathrm{x} .$ In question gev of $\mathrm{HCl}$ $\left(\frac{500 \times 2}{1000}=\operatorname{lgev}ight)$ and $\mathrm{NaOH}\left(\frac{250 \times 4}{1000}=\lg \mathrm{ev}ight)$
hence the value $x$.