Enthalpy of fusion and enthalpy of vaporization for water respectively are $6 \cdot 01 \mathrm{~kJ}…

Enthalpy of fusion and enthalpy of vaporization for water respectively are $6 \cdot 01 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $45 \cdot 07 \mathrm{~kJ} \mathrm{~mol}^{-1}$ at $0^{\circ} \mathrm{C}$ what is enthalpy of sublimation at $0^{\circ} \mathrm{C}$ ?
  1. $27 \cdot 50 \mathrm{~kJ} \mathrm{~mol}^{-1}$
  2. $48 \cdot 07 \mathrm{~kJ} \mathrm{~mol}^{-1}$
  3. $51 \cdot 08 \mathrm{~kJ} \mathrm{~mol}^{-1}$
  4. $39 \cdot 06 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Solution

$\Delta_{\text {fus }} \mathrm{H}=6.01 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $\Delta_{\mathrm{vep}} \mathrm{H}=45.07 \mathrm{~kJ} \mathrm{~mol}^{-1}, \Delta_{\mathrm{eub}} \mathrm{H}=?$ For sublimation at $0^{\circ} \mathrm{C}$, $\mathrm{H}_{2} \mathrm{O}_{(t)} \stackrel{\Delta H_{1} \rightarrow}{\longrightarrow} \mathrm{H}_{2} \mathrm{O}_{(\lambda)} \stackrel{\Delta \mathrm{H}_{2}}{\longrightarrow} \mathrm{H}_{2} \mathrm{O}_{(\varepsilon)}$ $\Delta_{\text {sub }} H=6.01+45.07=51.08 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Asked in: MHT CET 2020 (12 Oct Shift 1)

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