Energy of photon whose frequency is $10^{12} \mathrm{MHz}$ is [Planck's constant, $\mathrm{h}=6.63 \times…
Energy of photon whose frequency is $10^{12} \mathrm{MHz}$ is
[Planck's constant, $\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}, \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ ]
$4.14 \times 10^3 \mathrm{keV}$
$4.14 \times 10^2 \mathrm{eV}$
$4.14 \times 10^3 \mathrm{MeV}$
$4.14 \times 10^3 \mathrm{eV}$
Solution
Using plank energy quanta vs frequency relation:
$E(e V)=\frac{h v}{e}=\frac{6.63 \times 10^{-34} \times 10^{12} \times 10^6}{1.6 \times 10^{-19}}=4.14 \times 10^3 \mathrm{eV}$