Energy of a stationary electron in the hydrogen atom is E = - 13 . 6 n 2 eV then the energies required to excite the electron in hydrogen atom to (a) its second excited state and (b) ionized state respectively

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Aicharya · Accepted Answer

(a) For Hydrogen atom,
For ground state, $n = 1$ , energy is $E_{1} = \frac{- 13.6}{1^{2}} = - 13.6 eV$
For second excited state, $n = 3$ ,
Energy is $E_{2} = \frac{- 13.6}{{(3)}^{2}} = - 1.5 eV$
Energy required is $∆ E = E_{2} - E_{1} = - 1.5 + 13.6 = 12.1 eV \approx 12 eV$
(b) lonization energy is defined for ground state only, so ionized stated energy $= - E_{1} = 13.6 eV$

Energy of a stationary electron in the hydrogen atom is E = - 13 . 6 n 2 eV then the energies required to…

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