Emf of the following cell at 298 K in V is x×10-2ZnZn2+0.1M‖Ag+0.01MAgThe value of x is ________________ (Rounded off to the nearest integer)Given: EZn2+/Znθ=-0.76 V; EAg+/Agθ=+0.80 V; 2.303RTF=0.059