EMF of a cell in terms of reduction potential of its left and right electrodes is

EMF of a cell in terms of reduction potential of its left and right electrodes is
  1. $E=E_{\text {left }}-E_{\text {right }}$
  2. $E=E_{\text {left }}+E_{\text {right }}$
  3. $E=E_{\text {right }}-E_{\text {left }}$
  4. $E=-\left(E_{\text {right }}+E_{\text {left }}\right)$

Solution

$\begin{aligned} \mathrm{E}_{\text {cell }} & =\text { Reduction potential of cathode (right) - reduction potential of anode (left) } \\ & =\mathrm{E}_{\text {right }}-\mathrm{E}_{\text {left }}\end{aligned}$

Asked in: JEE Main 2002

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