Elevation in b.p. of an aqueous urea solution is $0.52^{\circ} .\left(\mathrm{K}_{\mathrm{b}}=0.52^{\circ} \mathrm{~mol}^{-1} \mathrm{~kg}ight.$ ).
Hence, mole-fraction of urea in this solution is

Question

Elevation in b.p. of an aqueous urea solution is $0.52^{\circ} .\left(\mathrm{K}_{\mathrm{b}}=0.52^{\circ} \mathrm{~mol}^{-1} \mathrm{~kg}ight.$ ). Hence, mole-fraction of urea in this solution is

Aicharya · Accepted Answer

$\Delta \mathrm{T}_{\mathrm{b}}=$ molality $\times \mathrm{K}_{\mathrm{b}}$
$0.52=m \times 0.52$
molality $=1 \mathrm{~mol} \mathrm{~kg}^{-1}$
$\therefore$ urea $=1 \mathrm{~mol}$
water $=\frac{1000}{18}=55.55$
mole fraction of urea $\frac{1}{55.55}=0.018$

Elevation in b.p. of an aqueous urea solution is $0.52^{\circ} .\left(\mathrm{K}_{\mathrm{b}}=0.52^{\circ}…

Solution