Electrons of mass, m with de-Broglie wavelength, λ fall on the target in an X-ray tube. The cutoff…

1. ${\mathrm{\lambda }}_0=\frac{2mc{\mathrm{\lambda }}^2}{h}$
2. ${\mathrm{\lambda }}_0=\frac{2h}{mc}$
3. ${\mathrm{\lambda }}_0=\frac{2m^2{c}^2{\mathrm{\lambda }}^3}{h^2}$
4. ${\mathrm{\lambda }}_0=\mathrm{\lambda }$

Solution

Asked in: NEET 2016 (Phase 2)

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