Electric potential at a point P due to a point charge of 5 × 10 - 9   C is 50   V . The distance of P from the point charge is: (Assume, 1 4 π ε 0 = 9 × 10 9   N   m 2   C - 2 )

Question

Electric potential at a point P due to a point charge of 5 &#215; 10 - 9 &#160; C is 50 &#160; V . The distance of P from the point charge is: (Assume, 1 4 &#960; &#949; 0 = 9 &#215; 10 9 &#160; N &#160; m 2 &#160; C - 2 )

Aicharya · Accepted Answer

The electric potential for a point charge is given by
$V = \frac{Q}{4 π ε_{0} r}$
The data given is
$V = 50 V Q = 5 \times 10^{- 9} C$
So, the distance of the point is
$r = \frac{1}{4 π ε_{0}} \frac{Q}{V}$
$\Rightarrow r = 9 \times 10^{9} \times \frac{5 \times 10^{- 9}}{50}$
$\Rightarrow r = 0.9 m = 90 cm$

Electric potential at a point P due to a point charge of 5 × 10 - 9   C is 50   V . The…

Solution

Electric potential at a point P due to a point charge of 5 &#215; 10 - 9 &#160; C is 50 &#160; V . The…

Solution

Electric potential at a point P due to a point charge of 5 × 10 - 9 C is 50 V . The…