Electric field represented by equipotential surface shown in figure is

Question

Aicharya · Accepted Answer

Dotted lines will give the direction of the electric field as in figure.

Distance between equipotential lines
$\begin{aligned} \Delta r &= 10 \cos 60^{\circ} = 5 \, \text{cm} \\ |\vec{E}| &= \left|\frac{\Delta V}{\Delta r}\right| = \frac{10}{5 / 100} = 200 \, \text{Vm}^{-1} \\ \vec{E} &= |\vec{E}| \hat{u} = 200\left[-\cos 60^{\circ} \hat{i} + \sin 60^{\circ} \hat{j}\right] \\ \vec{E} &= 200\left[-\frac{1}{2} \hat{i} + \frac{\sqrt{3}}{2} \hat{j}\right] \\ \vec{E} &= 100[-\hat{i} + \sqrt{3} \hat{j}] \, \text{N C}^{-1} \end{aligned}$

Electric field represented by equipotential surface shown in figure is

Solution