Edge length of unit cell of BCC structure is $352 \mathrm{pm}$. What is radius of the atoms?
Edge length of unit cell of BCC structure is $352 \mathrm{pm}$. What is radius of the atoms?
- 176.3 pm
- 304.8 pm
- 152.4 pm
- 252.4 pm
Solution
For BCC unit cell,
$\begin{aligned}
& 4 \mathrm{r}=\sqrt{3} \mathrm{a} \\
& \mathrm{r}=\frac{\sqrt{3} \mathrm{a}}{4}=\frac{1.732 \times 352}{4}=152.4 \mathrm{pm}
\end{aligned}$
Asked in: MHT CET 2021 (24 Sep Shift 1)
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