$16 \mathrm{~g}$ each of $\mathrm{H}_2$, He and $\mathrm{O}_2$ are present in a container exerting $10…
$16 \mathrm{~g}$ each of $\mathrm{H}_2$, He and $\mathrm{O}_2$ are present in a container exerting $10 \mathrm{~atm}$. pressure at $T(\mathrm{~K})$. The pressure in atm exerted by $16 \mathrm{~g}$ each of $\mathrm{He}$ and $\mathrm{O}_2$ in the second container of same volume and temperature is
1.8
6.4
3.6
5.4
Solution
Mixture of $\mathrm{H}_2$, He and $\mathrm{O}_2 16 \mathrm{~g}$ each exert $=10$ atm pressure.
Mixture of $\mathrm{He}, \mathrm{O}_2$ exert ( $16 \mathrm{~g}$ each) pressure $=$ ?
Mixture of $36 \mathrm{~g}$ exert pressure $=\frac{36}{10}=3.6$