Each interior angle of a regular pentagon measures:

Each interior angle of a regular pentagon measures:
  1. $100^{\circ}$
  2. $108^{\circ}$
  3. $120^{\circ}$
  4. $144^{\circ}$

Solution

Each interior angle $= \dfrac{(n-2) \times 180^{\circ}}{n} = \dfrac{3 \times 180^{\circ}}{5} = 108^{\circ}$.

Asked in: IMO

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