Each exterior angle of a regular pentagon is:

Each exterior angle of a regular pentagon is:
  1. $60^{\circ}$
  2. $72^{\circ}$
  3. $90^{\circ}$
  4. $108^{\circ}$

Solution

Each exterior angle $= \dfrac{360^{\circ}}{5} = 72^{\circ}$.

Asked in: IMO

Practice more UNDERSTANDING QUADRILATERALS questions on Aicharya