During the electrolytic reduction of alumina, the reaction at cathode is

During the electrolytic reduction of alumina, the reaction at cathode is
  1. $2 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{O}_2+4 \mathrm{H}^{+}+4 e^{-}$
  2. $3 \mathrm{~F}^{-} \longrightarrow 3 \mathrm{~F}+3 e^{-}$
  3. $\mathrm{Al}^{3+}+3 e^{-} \longrightarrow \mathrm{Al}$
  4. $2 \mathrm{H}^{+}+2 e^{-} \longrightarrow \mathrm{H}_2$

Solution

In electrolytic reduction of alumina at cathode $\mathrm{Al}^{3+}+3 e \longrightarrow \mathrm{Al}$

Asked in: AP EAMCET 2001

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