During discharging the change taking place at cathode in lead accumulator is

During discharging the change taking place at cathode in lead accumulator is
  1. $\mathrm{Pb}_{(\mathrm{s})}$ is oxidised to $\mathrm{Pb}_{(\text {aq. } .}^{2+}$
  2. $\mathrm{Pb}_{\text {(aq.) }}^{2+}$ is oxidised to $\mathrm{PbO}_{2(\mathrm{~s})}$
  3. $\mathrm{Pb} \mathrm{O}_{2(\mathrm{~s})}$ is reduced to $\mathrm{Pb}_{(\text {aq. })}^{2+}$
  4. $\mathrm{Pb}_{\text {(aq.) }}^{2+}$ is reduced to $\mathrm{Pb}_{(\mathrm{s})}$

Solution

During the discharging of a lead accumulator, the cathode $\left(\mathrm{PbO}_2\right)$ is converted to lead sulfate $\left(\mathrm{PbSO}_4\right)$. This is a chemical reaction that occurs when the accumulator is providing power.

Asked in: MHT CET 2020 (20 Oct Shift 1)

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