During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its…
- $\frac{4}{3}$
- 2
- $\frac{5}{3}$
- $\frac{3}{2}$
Solution
$\begin{aligned}
& p \propto T^3 \\
& p V=n R T \\
& \text { and } p \propto T^3 \\
& P \propto(p V)^3 \\
& \Rightarrow p^2 V^3=\text { constant } \\
& p V^{3 / 2}=\text { constant } \\
& \because p V^\gamma=\text { constant } \\
& \therefore \gamma=\frac{3}{2}
\end{aligned}$ /
Asked in: NEET 2013 (All India)