Due to surface tension, the excess pressure inside a smaller drop is 9 units. If 27 smaller drops of same…
- 18 units
- 9 units
- 6 units
- 3 units
Solution
Excess pressure Or Pressure jump $=2\left(\frac{\sigma}{r}\right)=9$ units
If 27 such drops combine, total volume is: $\mathrm{V}_{\mathrm{B}}=27 \mathrm{~V}_{\mathrm{S}}$
Using volume conservation:
$\begin{aligned}
& \frac{4}{3} \pi \mathrm{R}^3=27\left(\frac{4}{3} \pi \mathrm{R}^3\right) \\
& \Rightarrow \mathrm{R}=(3 \mathrm{r}) \\
& \therefore \text { Excess pressure }=\frac{2 \sigma}{\mathrm{R}}=\frac{2 \sigma}{3 \mathrm{r}}=3 \text { units }
\end{aligned}$Asked in: MHT CET 2022 (08 Aug Shift 2)
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