$y$ varies inversely as $x$. When $x = 15$, $y = 6$. The value of $y$ when $x = 9$ is:

$y$ varies inversely as $x$. When $x = 15$, $y = 6$. The value of $y$ when $x = 9$ is:
  1. $8$
  2. $10$
  3. $12$
  4. $14$

Solution

$xy = 15 \times 6 = 90$, so $y = \dfrac{90}{9} = 10$.

Asked in: IMO

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