$x^{3} - 27$ divided by $(x - 3)$ has remainder

$x^{3} - 27$ divided by $(x - 3)$ has remainder
  1. $0$
  2. $27$
  3. $-27$
  4. $3$

Solution

$p(3) = 27 - 27 = 0$.

Asked in: MH-SSC-9

Practice more Polynomials questions on Aicharya