$(x - 3)$ is a factor of $p(x) = x^{2} - 9x + 18$ because $p(3)$ equals

$(x - 3)$ is a factor of $p(x) = x^{2} - 9x + 18$ because $p(3)$ equals
  1. $0$
  2. $3$
  3. $18$
  4. $-3$

Solution

$9 - 27 + 18 = 0$.

Asked in: MH-SSC-9

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