$(x + 3)$ is a factor of $p(x) = x^{2} + 5x + 6$ if $p(-3)$ equals
$(x + 3)$ is a factor of $p(x) = x^{2} + 5x + 6$ if $p(-3)$ equals
- $0$
- $3$
- $-3$
- $6$
Solution
By factor theorem, factor iff $p(-3) = 0$. $p(-3) = 9 - 15 + 6 = 0$. ✓
Asked in: MH-SSC-9
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