$(x - 1)$ is a factor of $x^{n} - 1$ for

$(x - 1)$ is a factor of $x^{n} - 1$ for
  1. any positive integer $n$
  2. only $n = 2$
  3. only $n = 3$
  4. no $n$

Solution

$1^{n} - 1 = 0$ for any $n$.

Asked in: MH-SSC-9

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