$\triangle ABC \cong \triangle DEF$ by SSS implies $AB$ equals

$\triangle ABC \cong \triangle DEF$ by SSS implies $AB$ equals
  1. $DE$
  2. $EF$
  3. $DF$
  4. $BC$

Solution

Order: $A \leftrightarrow D, B \leftrightarrow E$. So $AB = DE$.

Asked in: MH-SSC-9

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