$\text { The current in the following circuit is }$

$\text { The current in the following circuit is }$
  1. $10 \mathrm{~A}$
  2. zero
  3. 0.025
  4. $10^{-2} \mathrm{~A}$

Solution

The diode is forward biased. Potential difference $=5-3=2 \mathrm{~V}$ $\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{2}{200}=10^{-2} \mathrm{~A}$ ~

Asked in: MHT CET 2021 (21 Sep Shift 1)

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