$\tan \left(\cos ^{-1} \frac{1}{\sqrt{2}}+\tan ^{-1} \frac{1}{2}\right)=$

$\tan \left(\cos ^{-1} \frac{1}{\sqrt{2}}+\tan ^{-1} \frac{1}{2}\right)=$
  1. 1
  2. 2
  3. 3
  4. 4

Solution

$\tan \left(\cos ^{-1} \frac{1}{\sqrt{2}}+\tan ^{-1} \frac{1}{2}\right)$
Let $\theta=\cos ^{-1} \frac{1}{\sqrt{2}}$ and $\phi=\tan ^{-1} \frac{1}{2}$ $\begin{aligned} & \therefore \quad \cos \theta=\frac{1}{\sqrt{2}} \text { and } \tan \phi=\frac{1}{2} \\ & \therefore \quad \tan \theta=1 \\ & \quad \text { Given expression }=\tan (\theta+\phi) \\ &=\frac{\tan \theta+\tan \phi}{1-\tan \theta \tan \phi} \\ &=\frac{1+\frac{1}{2}}{1-\frac{1}{2}}=3 \end{aligned}$

Asked in: MHT CET 2024 (10 May Shift 2)

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