$\sqrt{\dfrac{1}{16}} + \sqrt{\dfrac{1}{4}}$ equals

$\sqrt{\dfrac{1}{16}} + \sqrt{\dfrac{1}{4}}$ equals
  1. $\dfrac{3}{4}$
  2. $\dfrac{1}{8}$
  3. $\dfrac{1}{2}$
  4. $\dfrac{1}{4}$

Solution

$\dfrac{1}{4} + \dfrac{1}{2} = \dfrac{1 + 2}{4} = \dfrac{3}{4}$.

Asked in: IMO

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