$\sqrt{8} + \sqrt{2}$ equals

$\sqrt{8} + \sqrt{2}$ equals
  1. $3\sqrt{2}$
  2. $\sqrt{10}$
  3. $2\sqrt{2}$
  4. $\sqrt{16}$

Solution

$\sqrt{8} = 2\sqrt{2}$, so sum $= 2\sqrt{2} + \sqrt{2} = 3\sqrt{2}$.

Asked in: MH-SSC-9

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