$\sqrt{72} + \sqrt{32}$ in simplest form is
$\sqrt{72} + \sqrt{32}$ in simplest form is
- $10\sqrt{2}$
- $\sqrt{104}$
- $2\sqrt{26}$
- $8\sqrt{2}$
Solution
$\sqrt{72} = 6\sqrt{2}$, $\sqrt{32} = 4\sqrt{2}$. Sum $= 10\sqrt{2}$.
Asked in: MH-SSC-9
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