$\sqrt[3]{\dfrac{8}{27}}$ equals

$\sqrt[3]{\dfrac{8}{27}}$ equals
  1. $\dfrac{2}{3}$
  2. $\dfrac{3}{2}$
  3. $\dfrac{2}{9}$
  4. $\dfrac{8}{3}$

Solution

$\dfrac{\sqrt[3]{8}}{\sqrt[3]{27}} = \dfrac{2}{3}$.

Asked in: NSO

Practice more CUBES AND CUBE ROOTS questions on Aicharya