$p(x) = x^{3}$. Then $p(2) - p(-2)$ equals

$p(x) = x^{3}$. Then $p(2) - p(-2)$ equals
  1. $16$
  2. $0$
  3. $8$
  4. $-16$

Solution

$p(2) = 8$, $p(-2) = -8$. Difference $= 16$.

Asked in: MH-SSC-9

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