$p(x) = x^{2} - 4$. Then $p(2)$ is

$p(x) = x^{2} - 4$. Then $p(2)$ is
  1. $0$
  2. $4$
  3. $-4$
  4. $8$

Solution

$4 - 4 = 0$ (so $2$ is a zero).

Asked in: MH-SSC-9

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