$p(x) = x^{2} - 1$. Then $p(1) + p(-1)$ equals

$p(x) = x^{2} - 1$. Then $p(1) + p(-1)$ equals
  1. $0$
  2. $2$
  3. $-2$
  4. $1$

Solution

$p(1) = 0$, $p(-1) = 0$. Sum $= 0$.

Asked in: MH-SSC-9

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