$P, Q, R$ collinear with $PR = 10$, $PQ = 6$. If $Q$ is between $P$ and $R$, $QR$ is

$P, Q, R$ collinear with $PR = 10$, $PQ = 6$. If $Q$ is between $P$ and $R$, $QR$ is
  1. $4$
  2. $16$
  3. $60$
  4. $-4$

Solution

$QR = PR - PQ = 4$.

Asked in: MH-SSC-9

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