$\operatorname{cosec} 2 \theta-\cot 2 \theta=$
$\operatorname{cosec} 2 \theta-\cot 2 \theta=$
- $\tan \theta$
- $\sin 2 \theta$
- $\cos \theta$
- $\tan 2 \theta$
Solution
$\begin{aligned}
\operatorname{cosec} 2 \theta-\cot 2 \theta &=\frac{1}{\sin 2 \theta}-\frac{\cos 2 \theta}{\sin 2 \theta} \\
&=\frac{1-\cos 2 \theta}{\sin 2 \theta}=\frac{2 \sin ^{2} \theta}{2 \sin \theta \cos \theta}=\tan \theta
\end{aligned}$
Asked in: MHT CET 2020 (19 Oct Shift 1)
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