$\mathrm{P}_{4}+3 \mathrm{NaOH}+3 \mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{A}+3 \mathrm{NaH}_{2}…

$\mathrm{P}_{4}+3 \mathrm{NaOH}+3 \mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{A}+3 \mathrm{NaH}_{2} \mathrm{PO}_{2}$ here, ' $\mathrm{A}^{\prime}$ is
  1. $\mathrm{NH}_{3}$
  2. $\mathrm{PH}_{3}$
  3. $\mathrm{H}_{3} \mathrm{PO}_{4}$
  4. $\mathrm{H}_{3} \mathrm{PO}_{3}$

Solution

This is the laboratory method of preparing phosphine gas.
$$
\mathrm{P}_{4}+3 \mathrm{NaOH}+3 \mathrm{H}_{2} \mathrm{O} ightarrow \mathrm{PH}_{3}+3 \mathrm{NaH}_{2} \mathrm{PO}_{2}
$$
In this reaction, phosphorus disproportionate into phosphine and sodium hydrogen phosphite. ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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