$\mathrm{CH}_{3} \mathrm{Br}+\mathrm{Nu}^{-} \longrightarrow \mathrm{CH}_{3}-\mathrm{Nu}+\mathrm{Br}$ The…

$\mathrm{CH}_{3} \mathrm{Br}+\mathrm{Nu}^{-} \longrightarrow \mathrm{CH}_{3}-\mathrm{Nu}+\mathrm{Br}$
The decreasing order of the rate of the above reaction with nucleophiles $\left(\mathrm{Nu}^{-}ight) \mathrm{A}$ to $\mathrm{D}$ is
$\left[\mathrm{Nu}^{-}=(\mathrm{A}) \mathrm{PhO}^{-},(\mathrm{B}) \mathrm{AcO}^{-},(\mathrm{C}) \mathrm{HO}^{-},\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{O}^{-}ight]$
  1. $\mathrm{A}>\mathrm{B}>\mathrm{C}>\mathrm{D}$
  2. $B>D>C>A$
  3. $\mathrm{D}>\mathrm{C}>\mathrm{A}>\mathrm{B}$
  4. $\mathrm{D}>\mathrm{C}>\mathrm{B}>\mathrm{A}$

Solution

The acid character follows the order :
$\mathrm{CH}_{3} \mathrm{COOH}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{CH}_{3} \mathrm{OH}$
The basic character will follow the order $\mathrm{CH}_{3} \mathrm{COO}^{-} < \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-} < \mathrm{OH}^{-} < \mathrm{CH}_{3} \mathrm{O}^{-}$
The stronger the acid, the weaker the conjugate base formed.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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