$\lim _{x \rightarrow \frac{\pi}{2}} \frac{1+\cos 2 x}{\cot 3 x\left(3^{\sin 2 x}-1\right)}=$

$\lim _{x \rightarrow \frac{\pi}{2}} \frac{1+\cos 2 x}{\cot 3 x\left(3^{\sin 2 x}-1\right)}=$
  1. $\frac{1}{3 \log 9}$
  2. $\frac{2}{3 \log 3}$
  3. $\frac{1}{3 \log 3}$
  4. $\frac{3}{\log 3}$

Solution

$\lim _{x \rightarrow \frac{\pi}{2}} \frac{1+\cos 2 x}{\cot 3 x\left(3^{\sin 2 x}-1\right)} \Rightarrow \lim _{x \rightarrow \frac{\pi}{2}} \frac{2 \cos ^2 x}{\frac{\cos 3 x}{\sin 3 x} \times\left(3^{\sin 2 x}-1\right)}$ Let $x=\frac{\pi}{2}-h$, then $\lim _{h \rightarrow 0} \frac{2 \sin ^2 h}{\frac{\sin 3 h}{\cos 3 h}\left(3^{\sin 2 h}-1\right)}$ $ \begin{aligned} & =\lim _{h \rightarrow 0} \frac{2 \frac{\sin ^2 h}{h^2} \times h^2(\cos 3 h)}{\left(\frac{\sin 3 h}{3 h} \times 3 h\right) \frac{3^{\sin 2 h}-1}{\sin 2 h} \times \frac{\sin 2 h}{2 h} \times 2 h} \\ & =\frac{2 \times 1 \times 1}{(1 \times 3) \times\left[\log _e(3)\right] \times 1 \times 2}=\frac{1}{3 \log _e 3} \end{aligned} $

Asked in: AP EAMCET 2018 (22 Apr Shift 2)

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