$\lim _{x \rightarrow 0}\left(\frac{\sin a x}{\tan b x}\right)$ is equal to

$\lim _{x \rightarrow 0}\left(\frac{\sin a x}{\tan b x}\right)$ is equal to
  1. $a b$
  2. $\frac{a}{b}$
  3. $\frac{b}{a}$
  4. 1

Solution

$\lim _{x \rightarrow 0}\left(\frac{\sin a x}{\tan b x}\right)$ $ \lim _{x \rightarrow 0} a\left(\frac{\sin a x}{a x}\right) \times \lim _{x \rightarrow 0} \frac{1}{\left(\frac{\tan b x}{b x}\right) b}=a \times \frac{1}{b}=\frac{a}{b} $

Asked in: AP EAMCET 2021 (25 Aug Shift 1)

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