$\lim_{{x \rightarrow -}}\left(\frac{-\pi}{\cos(x)}\right)$ is equal to

$\lim_{{x \rightarrow -}}\left(\frac{-\pi}{\cos(x)}\right)$ is equal to
  1. $0$
  2. $\frac{1}{2}$
  3. $-2$
  4. $5$

Solution

Let $\ell=\lim _{x \rightarrow 2} \frac{\pi}{2}\left(\frac{2 x-\pi}{\cos x}\right) \quad\left[\right.$ form $\left.\frac{0}{0}\right]$ Use L' Hospital rule $=\lim _{x \rightarrow \pi / 2} \frac{2}{-\sin x}=\frac{2}{-1}=-2$

Asked in: AP EAMCET 2015

Practice more Limits questions on Aicharya