$\lim _{n \rightarrow \infty} n\left(\sqrt{n^2+9}-n\right)=$

Question

Aicharya · Accepted Answer

$\lim _{n \rightarrow \infty} n\left(\sqrt{n^2+9}-n\right)$ $\lim _{n \rightarrow \infty} \frac{n\left(n^2+9-n^2\right)}{\sqrt{n^2+9}+n}$ $\lim _{n \rightarrow \infty} \frac{9}{\sqrt{1+\frac{9}{n^2}}+1}=\frac{9}{2}$

$\lim _{n \rightarrow \infty} n\left(\sqrt{n^2+9}-n\right)=$

Solution