$\left(\mathrm{Si}_{2} \mathrm{O}_{5}ight)_{\mathrm{n}}^{2 \mathrm{n}-}$ anion is obtained when:

$\left(\mathrm{Si}_{2} \mathrm{O}_{5}ight)_{\mathrm{n}}^{2 \mathrm{n}-}$ anion is obtained when:
  1. no oxygen of a $\mathrm{SiO}_{4}^{4-}$ tetrahedron is shared with another $\mathrm{SiO}_{4}^{4-}$ tetrahedron
  2. one oxygen of a $\mathrm{SiO}_{4}^{4-}$ tetrahedron is shared with another $\mathrm{SiO}_{4}^{4-}$ tetrahedron
  3. two oxygen of a $\mathrm{SiO}_{4}^{4-}$ tetrahedron are shared with another $\mathrm{SiO}_{4}^{4-}$ tetrahedron
  4. three oxygen of a $\mathrm{SiO}_{4}^{4-}$ tetrahedron are shared with another $\mathrm{SiO}_{4}^{4-}$ tetrahedron

Solution



Total No. oxygen atoms per silicon atom
$=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+1=2.5$
$\therefore$ Formula $\mathrm{Si}_{2} \mathrm{O}_{5}^{2-}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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