$\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}ight)_{5} \mathrm{NO}ight]^{2+}$ is brown-ring complex in…
- $\mathrm{NO}$ transfers its electron to $\mathrm{Fe}^{2+}$ so that
there are three electrons unpaired making iron as $\mathrm{Fe(I)}$ and nitrosyl as $\mathrm{NO}^{+}$ - magnetic moment of Fe is $3.87 \mathrm{~BM}$
- the colour is due to charge transfer
- all are correct statements
Solution

Magnetic moment of $\mathrm{Fe}^{+}=\sqrt{15} \mathrm{~BM}$
$=3.87 \mathrm{~BM}$
Asked in: JEE-TOPICTESTS-CHEMISTRY
Practice more THE D AND F BLOCK ELEMENTS questions on Aicharya