$\left(\dfrac{a^{m}}{a^{n}}\right)^{p}$ equals
$\left(\dfrac{a^{m}}{a^{n}}\right)^{p}$ equals
- $a^{(m-n)p}$
- $a^{m-n+p}$
- $a^{m-np}$
- $a^{mp-n}$
Solution
$\dfrac{a^{m}}{a^{n}} = a^{m-n}$, then raised to $p$ gives $a^{(m-n) \cdot p}$.
Asked in: IMO
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