$\left(\dfrac{1}{2}\right)^{2} + \left(\dfrac{1}{3}\right)^{2}$ equals

$\left(\dfrac{1}{2}\right)^{2} + \left(\dfrac{1}{3}\right)^{2}$ equals
  1. $\dfrac{13}{36}$
  2. $\dfrac{5}{6}$
  3. $\dfrac{1}{6}$
  4. $\dfrac{2}{6}$

Solution

$\dfrac{1}{4} + \dfrac{1}{9} = \dfrac{9+4}{36} = \dfrac{13}{36}$.

Asked in: IMO

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