$\left(\dfrac{1}{2} + \dfrac{1}{3}\right) \times \left(\dfrac{1}{2} - \dfrac{1}{3}\right)$ equals
$\left(\dfrac{1}{2} + \dfrac{1}{3}\right) \times \left(\dfrac{1}{2} - \dfrac{1}{3}\right)$ equals
- $\dfrac{5}{36}$
- $\dfrac{1}{6}$
- $\dfrac{1}{36}$
- $0$
Solution
$(a+b)(a-b)=a^2-b^2 = \dfrac{1}{4}-\dfrac{1}{9} = \dfrac{5}{36}$.
Asked in: IMO
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