$\int_0^{\pi / 2} \log \left(\frac{4+3 \sin x}{4+3 \cos x}\right) d x=$

Question

Aicharya · Accepted Answer

Eq. (1) $+(2)$ gives, $2 I=\log \left[\frac{4+3 \sin x}{4+3 \cos x} 	imes \frac{4+3 \cos x}{4+3 \sin x}ight] d x=\int_0^{\frac{\pi}{2}}(\log 1) d x=0$

$\int_0^{\pi / 2} \log \left(\frac{4+3 \sin x}{4+3 \cos x}\right) d x=$

Solution