$\int_0^{2 \pi}(\sin x+|\sin x|) d x=$

Question

Aicharya · Accepted Answer

$\begin{aligned} & \int_0^{2 \pi}(\sin x+|\sin x|) d x= \ & =\int_0^\pi(\sin x+\sin x) d x+\int_0^\pi(\sin x-\sin x) d x \ & =\int_0^\pi 2 \sin x d x+0 \ & =[-2 \cos x]_0^\pi=4\end{aligned}$

$\int_0^{2 \pi}(\sin x+|\sin x|) d x=$

Solution