$\int_0^2 \frac{2 x-2}{2 x-x^2} d x$ is equal to

$\int_0^2 \frac{2 x-2}{2 x-x^2} d x$ is equal to
  1. $0$
  2. $2$
  3. $3$
  4. $4$

Solution

Let $I=\int_0^2 \frac{2 x-2}{2 x-x^2} d x$ Put $2 x-x^2=t \Rightarrow(2-2 x) d x=d t$ $ =-\int_0^0 \frac{d t}{t}=0 $

Asked in: AP EAMCET 2004

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